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Sample Technical Questions

C Sample Question

12. main()
    {
    	int c=- -2;
    	printf("c=%d",c);
    }

    Answer:

    c=2;

    Explanation:

    Here unary minus (or negation) operator is used twice. Same maths rules applies, ie. minus * minus= plus.

    Note:
    However you cannot give like --2. Because -- operator can only be applied to variables as a decrement operator (eg., i--). 2 is a constant and not a variable.

13. #define int char
    main()
    {
    	int i=65;
    	printf("sizeof(i)=%d",sizeof(i));
    }

    Answer:

    sizeof(i)=1

    Explanation:

    Since the #define replaces the string int by the macro char

14. main()
    {
    int i=10;
    i=!i>14;
    printf("i=%d",i);
    }

    Answer:

    i=0

    Explanation:

    In the expression !i>14 , NOT (!) operator has more precedence than ‘ >’ symbol. ! is a unary logical operator. !i (!10) is 0 (not of true is false). 0>14 is false (zero).

15. #include‹stdio.h›
    main()
    {
    char s[]={'a','b','c','\n','c','\0'};
    char *p,*str,*str1;
    p=&s[3];
    str=p;
    str1=s;
    printf("%d",++*p + ++*str1-32);
    }

    Answer:

    77

    Explanation:

    p is pointing to character '\n'. str1 is pointing to character 'a' ++*p. "p is pointing to '\n' and that is incremented by one." the ASCII value of '\n' is 10, which is then incremented to 11. The value of ++*p is 11. ++*str1, str1 is pointing to 'a' that is incremented by 1 and it becomes 'b'. ASCII value of 'b' is 98.
    Now performing (11 + 98 - 32), we get 77("M");
    So we get the output 77 :: "M" (Ascii is 77).

    #include‹stdio.h›
    main()
    {
    int a[2][2][2] = { {10,2,3,4}, {5,6,7,8}  };
    int *p,*q;
    p=&a[2][2][2];
    *q=***a;
    printf("%d----%d",*p,*q);
    }

    Answer:

    SomeGarbageValue---1

    Explanation:

    p=&a[2][2][2] you declare only two 2D arrays, but you are trying to access the third 2D(which you are not declared) it will print garbage values. *q=***a starting address of a is assigned integer pointer. Now q is pointing to starting address of a. If you print *q, it will print first element of 3D array.

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