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CAT Sample Questions ›› Quantitative

Quantitative Section : Quantitative Ability

Below we have given a few questions and answers on Multiple Choice. These questions will help you solve questions on multiple choices

Question 131: If the ratio of sec p to cosec f is 1:8, then the ratio of tan f to cot f is

1. 1:16
2. 4:45
3. 12:53
4. 9:2
5. 2:45

Explanation: The ratio which is given can be written in fractional form like sec f/cosec f = 1/8. The secant and cosecant can also be expressed in terms of sine and cosine. 1/cos f/1/sin f = 1/8. The cotangent is the reciprocal of the tangent so cot f = 4. Therefore the correct answer would be (a).

Question 132

If s – 8 = 8 (s – 2), then what is the value of s?

1. 8/7
2. 78/5
3. 157
4. 314
5. 2.45

Explanation: s – 8 = 8s -16
= - 8 + 16 = 8s – s
= 8 = 7s
S = 8/7

Question 133

If e varies directly as n and e/d = 10, then what is the value of e when d = 30?

1. 25
2. 0.23
3. 200
4. 78
5. 300

Explanation: Direct variation between two quantities means that they always have the same quotient. In this case, it means that e/d must always be equal to 10. To find the value of e when d = 30, set up the equation e/30= 10 and solve for p. You will find that e = 300

Question 134

(e3)6 * (e4)5/e2 =

1. e6
2. e18
3. re48
4. e36
5. e65

Explanation: A quick evaluation of exponent rules. When increasing the powers to powers; you need to multiply exponents. When multiplying the powers of the similar base include exponents and when dividing powers of the similar base, subtract exponents. For this problem you have to do all three to get correct answer.

Question 135

If the perimeter of a rectangle is 90, what is the area of the rectangle?

1. 324
2. 124
3. 965
4. 56
5. 324

Explanation: The opposite sides of the rectangle are the same. So the opposite side must be 18. Since the area of a rectangle is side2, therefore it is (18)2 = 324.

Question 136

Where defined, {y2 – 3/3} {8/2y + 3} =

1. 98
2. 56
3. – 11/3
4. 67y
5. 98y

Explanation: You can just factor this one and then cancel

{(y2 – 4/2)} {(16/24 + 2)} = {(y = 4) (y – 4) 4/2}{2*6/2(y + 2)}
= {y(y – 2) (8 + 2) = 2 * 6 (y + 2)
= - 20= 12y + 24
= - 20 – 24 = 12y
= y = - 11/3

Question 137: From this equation z(p) = 2k + 2, find the value of k, where p = 4 and z = 2

1. 10
2. 65k
3. 8p
4. 3

Explanation: Put the values of p and z in the equation to get the correct answer.
z(p) = 2k + 2
= 2(4) = 2k + 2
= 8 = 2k + 2
= 2k + 2 = 8
= 2k = 8 – 2
= 2k = 6
= k = 6/2
= k = 3. Therefore the correct answer is (e)

Question 138: If e(s) = |s| + 40 for which of the following values of s does e(s) = e(-s)?

1. 24
2. 2p
3. All real e
4. 56e
5. 25

Explanation: To start with the equation the statement e(s) = e(-s) when e = -40 and 40. A simple number like zero works best. e(0) = Ι0Ι + 20 = 20. You can see that e(0) = e(-0) so zero must be the part of correct answer, therefore (c) is the correct option.

Question 139: If log 6 = 8 then a =

1. 45/23
2. 78.45
3. 1.09
4. 4j
5. 32.45

Explanation: The equation log 6 = 8 in exponential form, j7 = 6. Now you have to find the value of a, you are required to take the 8th root of both the sides. You will see that a = 1.09. The correct option is (c).

Question 140: If 0 < d < 1 then all of the following must be true except:

1. 4:5
2. 56d
3. d < d
4. 23d
5. d<9

Explanation: First place the amount 0.5 in place of g. Now d3 = 0.25, cube root of n = 0.707, d = 0.5, - d = - 0.5, -d = -0.5, and 1/d = 2. This makes (a), (b), (d) and (e) true and (c) false.

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CAT Sample Quantitative Ability Question Number : 1-10 | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 | 81-90 | 91-100 | 101-110 | 11-120 | 121-130 | 131-140 | 141-150 | 151-160 | 161-170 | 171-180 | 181-190 | 191-200 | 201-210 | 211-220 | 221-230 | 231-240 | 241-250
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